Answer : The mass of oxygen involved in the reaction is, 32 grams.
Explanation : Given,
Mass of carbon monoxide = 56 g
Mass of carbon dioxide = 88 g
Molar mass of carbon monoxide [tex](CO)[/tex] = 28 g/mole
Molar mass of oxygen [tex](O_2)[/tex] = 32 g/mole
First we have to calculate the moles of carbon monoxide.
[tex]\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=\frac{56g}{28g/mole}=2moles[/tex]
Now we have to calculate the moles of oxygen gas.
The balanced chemical reaction will be,
[tex]2CO+O_2\rightarrow 3CO_2[/tex]
From the balanced chemical reaction, we conclude that
2 moles of CO react with 1 mole of [tex]O_2[/tex]
So, the moles of [tex]O_2[/tex] = 1 mole
Now we have to calculate the mass of oxygen.
[tex]\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2[/tex]
[tex]\text{Mass of }O_2=1mole\times 32g/mole=32g[/tex]
Therefore, the mass of oxygen involved in the reaction is, 32 grams.
