Here given cos Θ >0. That means cos Θ is positive.
We know that, cos Θ = (adjacent)/(hypotenuse) = [tex] \frac{x}{r} [/tex]
We also know that, hypotenuse can not be negative. So we will get cos positive where x co-ordinate is positive.
In first quadrant we will get positive x axis, in second quadrant there is negative x axis and same for third quadrant. In fourth quadrant we will get again positive x axis.
So cos is positive in first and fourth quadrant. Therefore, terminal side of theta lies in first and fourth quadrant.
We have got the required answer.
Option 1 and 4 is correct.
