Let f(x) = -2x^2 and g(x) = 2x - 4. On the set of axes, draw the graphs of y = f(x) and
y = g(x).
Using this graph, determine and state all values of x for which f(x) = g(x).

f(x) = -2x²
g(x) = 2x - 4

  f(x) = g(x)
-2x² = 2x - 4
-2x² - 2x = 2x - 2x - 4
-2x² - 2x + 4 = -4 + 4
-2x² - 2x + 4 = 0
-2(x²) - 2(x) - 2(-2) = 0
-2(x² - x - 2) = 0
  -2 -2
x² - x - 2 = 0
x² + 2x - x - 2 = 0
x(x) + x(2) - 1(x) - 1(2) = 0
  x(x + 2) - 1(x + 2) = 0
(x - 1)(x + 2) = 0
x - 1 = 0 or x + 2 = 0
+ 1 + 1 -  2 - 2
x = 1      or       x = -2
   f(x) = g(x)
  -2x² = 2x - 4
  -2(-2)² = 2(-2) - 4
     -2(4) = -4 - 4
  -8 = -8
or
  f(x) = g(x)
-2x² = 2x - 4
  -2(1)² = 2(1) - 4
  -2 = 2 - 4
-2 = -2

Solution Sets: {(-2, -8), (1, -2)}

Let f(x) = -2x^2 and g(x) = 2x - 4. On the set of axes, draw the graphs of y = f(x) and y = g(x). Using this graph, determine and state all values of x for which f(x) = g(x).

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Let f(x) = -2x^2 and g(x) = 2x - 4. On the set of axes, draw the graphs of y = f(x) and
y = g(x).
Using this graph, determine and state all values of x for which f(x) = g(x).