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In the reaction , Zn + HCl—> ZnCl2 + H2, 25 grams Zn are reacted with 17.5 grams HCl. How many grams of H2 will be produced ?
A. 0.382 g of H2
B. 0.479 g of H2
C. 0.7865 g of H2
D. 0.484 g of H2

Respuesta :

The full equation should be:
Zn + 2 HCl—> ZnCl2 + H2

The number of Zn atoms in reactant would be: 25g/(65.38g/mol)= 0.3824 mol
The number of HCl molecules in reactant would be: 17.5g/ (36.46g/mol)= 0.479mol

Since you use 2 HCl for each Zn, HCl would be depleted first. For every 2 HCl molecule, there will be 1 H2 formed.
The mass of H2 molecule formed would be: 0.479mol * 1/2 * 2g/mol = 0.479g
mahima6824soni

0.479 g of hydrogen will be produced if 25 grams Zn are reacted with 17.5 grams HCl.

What is hydrochloric acid?

Hydrochloric acid is an aqueous solution of hydrogen gas and chlorine gas.

The reaction is

[tex]\rm Zn + 2 HCl = ZnCl2 + H_2[/tex]

The number of moles present in Zn will be  

[tex]\rm \dfrac{25g}{65.38g/mol} = 0.3824 mol[/tex]

The number of moles present in HCl will be

[tex]\rm \dfrac{ 17.5g}{36.46g/mol} = 0.479mol[/tex]

The mass of hydrogen present is  [tex]\rm 0.479mol \times 1/2 \times 2g/mol = 0.479g[/tex]

Thus, The correct option is B. 0.479 g.

Learn more about HCL, here:

https://brainly.com/question/3637432

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