Respuesta :

Perry walked the farthest

Nadine = 6/24
Janet = 9/24
Perry = 20/24

Perry walked 7/12 miles more than Nadine.

Hope this helps.

Answer:

Perry walked the farthest.

Perry walked [tex]\frac{7}{12}[/tex] of a mile farther than Nadine.

Step-by-step explanation:

We have been given that Nadine walked 1⁄4 of a mile, Janet walked 3⁄8 of a mile, and Perry walked 5⁄6 of a mile.

To find who walked the farthest, we will compare our given fraction by making a common denominator.

[tex]\frac{1}{4}.\frac{3}{8},\frac{5}{6}[/tex]

We know that 24 is the least common multiple of 4, 6 and 8, so we can have a common denominator as:

[tex]\frac{1*6}{4*6}.\frac{3*3}{8*3},\frac{5*4}{6*4}[/tex]

[tex]\frac{6}{24}.\frac{9}{24},\frac{20}{24}[/tex]

Since [tex]\frac{20}{24}[/tex] in the greatest of the given fractions, therefore, Perry walked the farthest.

To find the difference between distance walked by Perry and Nadine, we will subtract [tex]\frac{1}{4}[/tex] from [tex]\frac{5}{6}[/tex].

[tex]\frac{5}{6}-\frac{1}{4}[/tex]

[tex]\frac{5*2}{6*2}-\frac{1*3}{4*3}[/tex]

[tex]\frac{10}{12}-\frac{3}{12}[/tex]

[tex]\frac{10-3}{12}=\frac{7}{12}[/tex]

Therefore, Perry walked [tex]\frac{7}{12}[/tex] of a mile farther than Nadine.