Leslie ran a three– mile race. The second mile took her 10 percent longer than the first mile, and the third mile took her 24 seconds longer than the second mile. If Leslie's total time for the race was 26 minutes, how long did the second mile take her?

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Canfengchen123 Canfengchen123 · Answer 1 · 2018-04-04T22:19:51+02:00

[tex]x + 1.1x + 1.1x + 24 = 1560[/tex]
x=480
2nd mile=528 seconds

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Riia Riia · Answer 2 · 2018-08-23T04:16:16+02:00

Let for first mile, she took x minutes . And second mile took her 10 percent longer, so second mile took

[tex] x+ \frac{10}{100}x = \frac{110}{100}x = 1.1x [/tex]

And the third mile took 24 seconds longer as compared to second mile .

So third mile took

[tex] 1.1x + \frac{24}{60} = (1.1x +0.4) minutes [/tex]

And the total time for the race was 26 minutes, that is

[tex] x+1.1x + 1.1x +0.4 = 26 [/tex]

[tex] 3.2x = 26-0.4
\\
3.2x = 25.6
\\
x = \frac{25.6}{3.2} = 8 minutes [/tex]

So the first mile took 8 minutes. And therefore second mile took

[tex] =1.1(8) = 8.8 minutes [/tex]