HMHorton2006
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you compared the two functions below. f(x) = 1.2t      g(x) = 1.2t-5
What did subtracting 5 in the exponent do to the function? Check all that apply.
A. It shifts the graph of f left 5 units.
B. It shifts the graph of f right 5 units.
C. It multiplies all the y-values by 5.
D. It divides all the y-values by 5.
E. It multiplies all the y-values by 1.25.
F. It divides all the y-values by 1.25.

Respuesta :

the second and the last are the correct ones
thaovtp1407

Answer:

B. It shifts the graph of f right 5 units.

F. It divides all the y-values by 1.25.

Step-by-step explanation:

Let me revise your two functions:

f(x) = [tex]1.2^{t}[/tex]

g(x) = [tex]1.2^{t-5}[/tex]

So g(x) is the transformed function of f(x), as we know that

  • if we subtract anything from x or t (independent variable), the graph will move right.
  • if we add anything from x or t (independent variable), the graph will move left.

In this situation, we subtract 5 from it, so the graph of f right 5 units.

However, it also affect to the value of y, I will rewrite g(x)

g(x) = [tex]\frac{1.2^{t} }{1.2^{5} }[/tex] = [tex]1.2^{t}[/tex] *[tex]\frac{1}{1.25^{5} }[/tex] = [tex]\frac{1}{1.25^{5} }[/tex] f(x)

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