Respuesta :
Electric force is the attractive or reflective force of interception between two charged object.
- A) The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.
- B) The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.
Given information-
The mass of first object is 6 kg.
The mass of second object is 17 kg.
The charge on both the object is 0.027 C.
The distance between the two object is 3 m.
What is electric force?
Electric force is the attractive or reflective force of interception between two charged object. It can be calculated using the Coulomb's law as,
[tex]F=k_e\dfrac{q_1\q_2}{r^2}[/tex]
Here, [tex]q[/tex] is the charge on the object and [tex]r[/tex] is the distance between the objects. [tex]k_e[/tex] is coulombs constant [tex](8.987\times 10^9)[/tex] N-m squared per C squared.
- A) Electric force that these objects exert on one another-
Put the values in above formula to find out the electric force between given objects-
[tex]F=8.987\times10^9\dfrac{(-0.027)\times(-0.027)}{3^2}\\F=7.28\times 10^5[/tex]
Hence the electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.
- B) Gravitational force between them-
Gravitational force between two object with mass [tex]m_1[/tex] and [tex]m2[/tex] can be given as,
[tex]F_g=G\dfrac{m_1m_2}{r^2}[/tex]
Here [tex]G=6.67\times 10^{-11}[/tex] N-m squared per kg squared.
Put the values,
[tex]F_g=6.67\times 10^{-11}\times\dfrac{6\times17}{3^2}\\F_g=7.56\times10^{-10}[/tex]
Thus, the gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.
Hence,
- The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.
- The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.
Learn more about the electric force here;
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