the balanced equation for the above reaction is as follows;
3NaOH + H₃PO₄ ---> Na₃PO₄ + 3H₂O
stoichiometry of NaOH to H₃PO₄ is 3:1
the number of NaOH moles in the solution - molarity x volume
number of NaOH moles - 0.3 mol/L x 0.030 L = 0.009 mol
for complete neutralisation
3 mol of NaOH requires 1 mol of H₃PO₄
therefore 0.009 mol of NaOH requires - 1/3 x 0.009 = 0.003 mol of H₃PO₄
therefore 0.003 mol of H₃PO₄ are needed to reach the equivalence point
