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Sina played basketball on a rectangular court that was 74 feet by 42 feet. after the game, she walked across the court diagonally from one corner to the opposite corner. approximately what distance did sina walk in feet?

Respuesta :

Distance walked = 85.088 feet


The distance Sina walked would be equal to the length of the diagonal of rectangle.

As every angle in a rectangle is 90 degree. So, we can apply Pythagoras theorem in right triangle formed by sides,

Base- 74 feet, Altitude-  42 feet and Hypotenuse- Diagonal

Base^2 + Altitude ^ 2 = Hypotenuse ^2

74^2 + 42 ^ 2 = Diagonal ^2

On solving,

Diagonal = 85.088 feet

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