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If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific heat capacity of the metal?

Respuesta :

kenmyna
The specific  heat  capacity  of the  metal  is calculated  using  the  following  formula
Q(heat)= MC delta T
Q= 1495 j
c= specific heat   capacity =?
M(mass)=319 g
delta T = change  in  temperature = 66-55 =11 c
by  making   c  the subject  of the formula 

  C=Q /M delta T
c= 1495 j/ 319 g  x 11 c =0.426 j/g/c

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