A spring is stretched 175 mm by an 8-kg block. the block is displaced 100 mm downward from its equilibrium position and given a downward velocity of 1.50 m/s. assume that positive displacement y is downward.
Let spring K be constant K= F/x = mg/x = (8kg)(9.81 m/s)/175 × 10⁻³m = 448.46 N/m The angular of spring's frequency is w = √k/√m = √448.46/√8 = 7.49 rad/s
∴ differential equation y¹¹ + (7.49)² y = 0 y¹¹ ₊ 56.1 where y = 0.
