Respuesta :

gmany
[tex]5\cdot\dfrac{x^2-2x}{6}:\dfrac{3x-6}{x}=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3x-6}\\\\=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3(x-2)}=\dfrac{5\cdot x\cdot x}{6\cdot3}=\dfrac{5x^2}{18}[/tex]