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03-06-2018
Mathematics

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Find the value of x in each case. PLEASE SHOW WORK!!!

Find the value of x in each case PLEASE SHOW WORK class=

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03-06-2018

[tex]m\angle BCA=180^o-5x[/tex]

[tex]\angle CAB=\angle ACD\\\\m\angle CAB=33^o[/tex]

In the triangle ABC:

[tex]m\angle ABC+m\angle BCA+m\angle CAB=180^o\\\\2x+180^o-5x+33^o=180^o\\\\-3x+213^o=180^o\ \ \ |-213^o\\\\-3x=-33^o\ \ \ |:(-3)\\\\x=11^o[/tex]

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