Respuesta :
Molar Mass of Lead (Pb) = 207
Molar Mass of Oxygen (O) = 16
So, Mass of Molar Mass(Mass of 1 mole) of PbO₂ = 207 + 2(16) = 239 grams
Mass of 3.7 moles of PbO₂ = 3.7 x 239 = 884 grams
Thus the mass of 3.7 mol PbO₂ is 884 grams. So option B gives the correct answer.
Molar Mass of Oxygen (O) = 16
So, Mass of Molar Mass(Mass of 1 mole) of PbO₂ = 207 + 2(16) = 239 grams
Mass of 3.7 moles of PbO₂ = 3.7 x 239 = 884 grams
Thus the mass of 3.7 mol PbO₂ is 884 grams. So option B gives the correct answer.
Answer: The mass of given moles of [tex]PbO_2[/tex] is 884 grams.
Explanation:
To calculate the mass of a compound, we use the following equation:
[tex]\text{Number of moles}=\frac{\text{Given mass of compound}}{\text{Molar mass of compound}}[/tex]
We are given:
Moles of lead (iv) oxide = 3.7 mol
Molar mass of lead (iv) oxide = 239 g/mol
Putting values in above equation, we get:
[tex]3.7mol=\frac{\text{Mass of lead (iv) oxide}}{239g/mol}\\\\\text{Mass of lead (iv) oxide}=884g[/tex]
Hence, the mass of given moles of [tex]PbO_2[/tex] is 884 grams.
