Respuesta :

ktreyb
y - 1 = 2(x - 2)
y - 1 = 2x - 4
y = 2x - 4 + 1
y = 2x - 3

So first thing you look for is whichever graph has a y-intercept at y = - 3. Any of the graphs that DON'T have a y-intercept at (0, - 3) can be eliminated. The only one that does is the first graph so... 

Your answer is the first graph. 
kanest
This equation is in point-slope form, which uses the following formula:

[tex]y - y_{1} = m(x - x_{1})[/tex]

x₁ and y₁ represent the values of a point on the graph, and m is the slope of the graph.

This equation has 2 for its x₁ value, and 1 for its y₁ value. Therefore, we are looking for a line that passes through (2,1).

The first graph passes through (2,1). The second, third, and fourth graph do not pass through (2,1). 

The first graph represents y – 1 = 2(x – 2).