Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s. If Tyler catches his friend, how fast will they move on the skateboard?

Momentum question. This is an inelastic collision, so

m1v1+m2v2=Vf(m1+m2)
Vf=(m1v1+m2v2)/(m1+m2)=[(120kg)(0m/s)+(60kg)(2m/s)] / (120kg+60kg)
Vf=120kg m/s / 180kg
Vf=0.67m/s

0.67m/s

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sp10925 sp10925 · Answer 2 · 2022-07-20T16:39:50+02:00

The skateboard will move with the speed of 0.67m/s.

What is conservation of momentum principle?

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

m₁u₁ +m₂u₂ =(m₁ +m₂) v

Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s.

Substitute the values, then the final velocity will be

v =[(120)(0)+(60)(2)] / (120+60)

v =120/180

v =0.67m/s

Thus, the skateboard will move with 0.67m/s.

Learn more about conservation of momentum principle

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