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2fe(no3)3 + 3na2co3 → fe2(co3)3 + 6nano3 how many moles of nano3 are produced when 1.0 moles of fe(no3)3 reacts with excess sodium carbonate?

Respuesta :

SvetkaChem
2Fe(NO3)3 + 3Na2CO3 → Fe2(CO3)3 + 6NaNO3
2 mol                                                          6 mol
1 mol                                                          3 mol

3 mol NaNO3

Answer:

number of moles of NaNo3  produced = 3 moles

Explanation:

From the equation 2 moles of Iron (iii) nitrate reacted  with 3 moles of sodium carbonate to form 1 mole of iron(iii) carbonate and 6 moles sodium trioxonitrate.

Check whether the equation is balanced

2fe(No3)3 + 3Na2co3 → fe2(co3)3 + 6NaNo3

The equation is balanced.

From the equation

2 moles of fe(No3)3 produces  6 moles of  NaNo3

1 mole  of  fe(No3)3 will produce ?

cross multiply

number of moles of NaNo3  produced = 6/2

number of moles of NaNo3  produced = 3 moles

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