Answer:
Equation in point-slope form : [tex](y-0)=\frac{-3}{5}(x-3)[/tex]
Equation in Slope-intercept form : [tex]y=\frac{-3}{5}x+\frac{9}{5}[/tex]
Step-by-step explanation:
Given point on the line are ( - 2 , 3 ) and ( 3 , 0 )
We need to write the equation of line in point-slope form and slope-intercept form.
Slope of the line = [tex]\frac{3-0}{-2-3}=\frac{-3}{5}[/tex]
Equation in Point Slope form is written as,
[tex](y-y_1)=m(x-x_1)[/tex]
So, Equation in point-slope form : [tex](y-0)=\frac{-3}{5}(x-3)[/tex]
Equation in Slope-intercept form is written as,
[tex]y=mx+c[/tex]
So, Equation in point-slope form :
[tex](y-0)=\frac{-3}{5}(x-3)[/tex]
[tex](y-0)=\frac{-3}{5}(x-3)[/tex]
[tex]y=\frac{-3}{5}x-\frac{-3}{5}\times3[/tex]
[tex]y=\frac{-3}{5}x+\frac{9}{5}[/tex]
