Respuesta :

midknight9
Through manipulation of equations, we are able to obtain the equation:

[tex]-pOH= log [ OH^{-}] [/tex]

Then we can transform the equation into:

[tex][ OH^{-}]= 10^{-pOH} [/tex]

Then we are able to plug in the pOH and directly get [OH-]:

[tex][ OH^{-}] = 10^{-6.48} [/tex]

[tex][ OH^{-}]=3.31* 10^{-7} M [/tex]

The pOH value of the given solution is 6.48, the [OH⁻¹] concentration in the solution is 3.37×10⁻⁷.

What is the pOH value?

pOH value is a negative log value of  [OH⁻¹] concentration in a solution, a measure of [OH⁻¹]ion concentration of a solution

pOH can also be calculated by 14 – pH, now convert value of 6.48 back into its concentration    

-pOH= log  [OH⁻¹]

 [OH⁻¹] =log⁻⁶°⁴⁸            

        = 3.37 × 10⁻⁷  

Convert the value in its respective given log value and simplify it, the ×  sign gets converted into + in the solution.

                                                         

Hence, the concentration of the given solution is 3.37×10⁻⁷

Learn more about pH.

https://brainly.in/question/1201953

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