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in 2005 the number of federal hazardous waste sites in California was 2 less than twice the number of sides in Washington how many hazardous waste sites were there in Washington if they're worth 42 such sites in California

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midknight9
Let's just take each bit of information separately first:

Let x = number of waste sites in Washington

Number of sites in California = 2x - 2

We know that there were 42 sites in California, so we can then solve for x:

[tex]42=2x-2[/tex]
[tex]44=2x[/tex]
[tex]22=x[/tex]

So now we know that there were 22 waste sites in Washington.
DeanR
Let [tex]c[/tex] be the number of California sites and [tex]w[/tex] be the number of Washington sites.

[tex]c = 2w - 2[/tex]

[tex]c = 42[/tex]

[tex]42 = 2w - 2[/tex]

[tex]44 = 2w[/tex]

[tex]w=22[/tex]

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