It can be helpful to draw a diagram. (See the attached.)
There are a number of ways to find the resultant speed and direction. Here, we will make use of the Law of Cosines and the Law of Sines. We have two sides of the speed triangle and the angle between them, so we can use the Law of Cosines to find the resultant speed (s).
s² = 1.25² +3.53² -2·1.25·3.53·cos(62.5°) ≈ 9.948468
s ≈ √9.948468 ≈ 3.154119 . . . . miles per hour
Then the Law of Sines can be used to find the obtuse angle between the direction of the current and the direction of the boat in the current. That angle (α) will satisfy
sin(α)/3.53 = sin(62.5°)/3.154119
α = arcsin(3.53·sin(62.5°)/3.154119) ≈ 96.919153°
That is, the boat's path is 6.919° west of north. The tangent of this angle gives the ratio between the upstream distance traveled and the across-stream distance traveled (Tan = Opposite/Adjacent). We know the across-stream distance is 0.900 miles, so the upstream distance is
upstream distance = tan(6.919°)·0.900 mi ≈ 0.1092 mi
The boat is 0.1092 miles upstream when it reaches the opposite shore.
