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Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 12.0 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.

Respuesta :

PBCHEM
Answer : 5100 KJ

Explanation : In the given reaction of 

[tex] Fe_{2} O_{3} + 2Al ----\ \textgreater \ Al_{2}O_{3} + 2Fe[/tex]

we can see that 2 moles of Al is producing -850 KJ of energy

so for 12 moles of Al we can calculate as;

12 moles of Al X[tex] \frac{-850}{2 moles of Al} [/tex] = -5100 KJ

So, we can say that 12 moles of Al will need -5100 KJ of energy.

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