Respuesta :
Molarity (M) = moles of solute (mol) / Volume of the solution (L)
Molarity of the solution = 3.000 M
Volume of the solution = 250.0 mL = 0.25 L
moles in 250.0 mL = molarity x volume of the solution
= 3.000 M x 0.25 L
= 0.75 mol
Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.
Moles (mol) = mass (g) / molar mass (g/mol)
Moles of NaCl in 250.0 mL = 0.75 mol
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl in 250.0 mL = Moles x Molar mass
= 0.75 mol x 58.44 g/mol
= 43.83 g
Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.
Molarity of the solution = 3.000 M
Volume of the solution = 250.0 mL = 0.25 L
moles in 250.0 mL = molarity x volume of the solution
= 3.000 M x 0.25 L
= 0.75 mol
Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.
Moles (mol) = mass (g) / molar mass (g/mol)
Moles of NaCl in 250.0 mL = 0.75 mol
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl in 250.0 mL = Moles x Molar mass
= 0.75 mol x 58.44 g/mol
= 43.83 g
Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.
Answer:
43.83 grams of NaCl are required to make 250 ml of a 3M solution.
Explanation:
As given in the question,
Molarity of solution= 3M
Volume of solution= 250ml
Weight of solute Nacl=?
The formula for molarity is,
[tex]\rm Molarity=\frac{\texttt{Numbers of moles}}{\texttt{volume of solution}}\times1000[/tex]
[tex]\rm 3=\frac{\texttt{number of moles}}{\texttt{250ml}}\times1000[/tex]
[tex]\rm \texttt{Number of moles}=\frac{3}{4}[/tex]
Number of moles=0.75 moles
According to the formula,
[tex]\rm \texttt{Number of moles}=\frac{\texttt{given mass}}{\texttt{molecular mass}}[/tex]
As we know, the molecular mass of NaCl is 58.44
Hence,
[tex]0.75=\frac{\texttt{Given mass}}{58.44}[/tex]
[tex]\texttt{Given mass}=43.83\text{grams}[/tex]
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