Answer:
Twelve is not an outlier because it is less than the sum of 7 and 6.
Step-by-step explanation:
:)
The correct option is Option D: twelve is not an outlier because it is less than the sum of 7 and 6.
The outlier of a dataset is the data that is distant from other values of the dataset.
Here, Given {2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12} is the dataset
number of observations is N=11
interquartile range (IQR)= 4
Then The position of lower quartile of the above set is:
Q₁=1/4*(N+1)th
⇒Q₁=1/4*(11+1)th
⇒Q₁=1/4*(12)th
⇒Q₁=3rd
The 3rd element is 3 thus Q₁=3
Similarly, the position of upper quartile of the above set is:
Q₃=3/4*(N+1)th
⇒Q₃=3/4*(11+1)th
⇒Q₃=3/4*(12)th
⇒Q₃=9th
The 9th element is 7 thus Q₃=7
The lower outlier (L) is
L=Q₁-(1.5*IQR)
⇒L=3-(1.5*4)
⇒L=3-6
⇒L=-3
The upper outlier (U) is:
U=Q₃+(1.5*IQR)
⇒U=7+(1.5*4)
⇒U=13
Values from lower to upper outliers are not outliers.
In another way,
[-3,-2,-1,0,1,2,3........11,12,1,3} are not outliers.
12 is not an outlier as it is less than 13.
13 is calculated by 7 + 6; as in: U=7+6
Therefore twelve is not an outlier because it is less than the sum of 7 and 6.
Learn more about outliers
here: https://brainly.com/question/12153650
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