so, we know the snow plow tire turned or went around 29 times, namely 29 revolutions, and recall that one revolution is a 2π angle in radians.
since the tire went around 29 times, so it made an angle of 29 * 2π, or 58π.
we know the street is 116 meters long, namely "an arc made by that 58π angle is 116".
[tex]\bf \textit{arc's length}\\\\
s=r\theta ~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=116\\
\theta =58\pi
\end{cases}\implies 116=r58\pi \implies \cfrac{116}{58\pi }=r
\\\\\\
\cfrac{2}{\pi }=r\qquad \qquad\qquad \qquad \stackrel{\textit{a \underline{d}iameter is twice the radius}}{2\left( \cfrac{2}{\pi } \right)=d\implies \cfrac{4}{\pi }=d}[/tex]
