2.25:1
Substitute the "new" velocity (I.e. "1.5v") into the dynamic pressure equation:
q = (1/2)*n*[(1.5v)^(2)]
=> q= (1/2)*n*[2.25v^(2)]
Compare this result to dynamic pressure with a velocity of "v":
q = (1/2)*n*[v^2]
As you will see, the faster fluid has a dynamic pressure, q, value that is 2.25x greater than that of the slower fluid.
Therefore, the ratio of the faster fluid to the slower fluid is 2.25 to 1.
