You accelerate your car from rest at a constant rate down a straight road, and reach 22.0 m/s in 117 s. the tires on your car have radius 0.320 m. assuming the tires rotate in a counterclockwise direction, what is the angular acceleration of the tires?

Respuesta :

For this case, the first thing to do is find the linear acceleration of the car.

We have then:

[tex] a = \frac{v}{t}
[/tex]

Where,

v: speed

t: time

Substituting values we have:

[tex] a = \frac{22}{117}
[/tex]

[tex] a = 0.19 \frac{m}{s^2}
[/tex]

We are now looking for angular acceleration.

For this, we use the following equation:

[tex] \alpha =\frac{a}{r} [/tex]

Where,

a: linear acceleration

r: radius of the tires

Substituting values we have:

[tex] \alpha = \frac{0.19}{0.320}
[/tex]

[tex] \alpha = 0.59 \frac{rad}{s^2} [/tex]

Answer:

The angular acceleration of the tires is:

[tex] \alpha = 0.59 \frac{rad}{s^2} [/tex]