Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg. How many toys did Oleg have?

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Respuesta :

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

[tex] x + y + z = 600 [/tex]

[tex] x + 2x + x + 40 = 600 [/tex]

[tex] 4x + 40 = 600 [/tex]

Subtract 40 on both sides

[tex] 4x = 600 - 40 [/tex]

Divide by 4 on both sides

[tex] x = \frac{560}{4} = 140 [/tex]

Oleg had 140 toys