Respuesta :
Let [tex] f [/tex] be the weight of the fresh coffee, and [tex] r [/tex] be the weight of the roasted coffee. The equation described by the first sentence is
[tex] r = f\cdot \cfrac{88}{100} = f\cdot \cfrac{22}{25} [/tex]
In this case, we know [tex] r [/tex] and want to solve for [tex] f [/tex]: the equation becomes
[tex] 14225 = f\cdot \cfrac{22}{25} [/tex]
To solve for [tex] f [/tex], multiply both sides by 25/22:
[tex] 14225 \cdot \cfrac{25}{22}= f\cdot \cfrac{22}{25} \cdot \cfrac{25}{22}[/tex]
[tex] f = 14225 \cdot \cfrac{25}{22} = \cfrac{355625}{22} \approx 16164.77[/tex]
Alright, lets get started.
Let me first share my double, its 14.225 lb or 14225 lb written in question.
I am considering 14.225 lb.
Lets suppose we have x lb coffee before roasting.
As given in question, it loses 12 % of its weight while roasting.
Means the rest weight of coffee after roasting = x - x * 12%
the rest weight of coffee after roasting = x - 0.12 x
the rest weight of coffee after roasting = 0.88 x
As per given in question, the weight after roasting = 14.225 lb
Equalling both
0.88x = 14.225
Dividing by 0.88
0.88x / 0.88 = 14.225 / 0.88
x = 16.1647 lb
Means we need to get 16.1647 lb coffee in order to get 14.225 lb : Answer
Hope it will help.
If 14225 lb is written in question , then calculation will be
x = 14225/0.88 = 16164.77 lb
Hope it will help :)
