First find the MCM of both fractions:
[tex] \frac{1}{2} + \frac{2}{3} = \frac{3}{6} + \frac{4}{6} [/tex]
After that do the sum normally:
[tex] \frac{3}{6} + \frac{4}{6} = \frac{7}{6} = 1 \frac{1}{6} [/tex]
Hope it helped,
Happy homework/ study/ exam!
Here we have to find lcm of 2 and 3 first
lcm of 2 and 3 is 2*3=6
now we convert both denominator into lcm
[tex] \frac{1}{2} +\frac{2}{3} [/tex]
[tex] \frac{1*3}{2*3} +\frac{2*2}{3*2} [/tex]
[tex] \frac{3}{6} +\frac{4}{6} [/tex]
combining numerators
[tex] \frac{3+4}{6} [/tex]
=7/6
