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A runner accelerates to a velocity of 5.36 m/s due west in 3.00 seconds. his average acceleration is 0.640 m/s2 also directed due west. what was his velocity when he began accelerating?

Respuesta :

I18ntech

Given, acceleration of the runner, a = 0.640 m/s²

Final velocity of the runner, v = 5.36 m/s

Time, t = 3 s

Let the velocity of the runner be u when he began accelerating.

Using the first equation of motion,

v=u+at

Substituting the values we get,

[tex] 5.36= u + 0.64*3 [/tex]

[tex] u=5.36-1.92 [/tex]

=3.44 m/s

The velocity of the runner when he began accelerating is 3.44 m/s.

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