PLEASE HELP Consider the three functions below.


f(x) = -6/11(11/2)x g(x) = 6/11 (11/2)-x h(x) = -6/11 (11/2)-x


Which statement is true?


A)The range of h(x) is y > 0.


B)The domain of g(x) is y > 0.


C)The ranges of f(x) and h(x) are different from the range of g(x).


D) The domains of f(x) and g(x) are different from the domain of h(x).

Respuesta :

If these are supposed to be exponential functions

[tex]\displaystyle f(x)=-\frac{6}{11}\left(\frac{11}{2}\right)^{x}\\\\g(x)=\frac{6}{11}\left(\frac{11}{2}\right)^{-x}\\\\h(x)=-\frac{6}{11}\left(\frac{11}{2}\right)^{-x}[/tex]

Then they are all defined for all real numbers, so all have the same domain. The range of f and h will be (-∞, 0) and the range of g will be (0, ∞), so these are different.

The appropriate statement choice is ...

... C)The ranges of f(x) and h(x) are different from the range of g(x).


[tex]f(x)=\frac{-6}{11}*(\frac{11}{2} )^{x}[/tex]

Domain : All real numbers since this is an exponential function.

Range : (-∞,0)

[tex]f(x)=\frac{6}{11}*(\frac{11}{2} )^{-x}[/tex]

Domain : All real numbers since this is an exponential function.

Range : (0,∞)

[tex]f(x)=\frac{-6}{11}*(\frac{11}{2} )^{-x}[/tex]

Domain : All real numbers since this is an exponential function.

Range : (-∞,0)

So Option C  : )The ranges of f(x) and h(x) are different from the range of g(x).