Respuesta :
The given equation is [tex] 5\sqrt{x+7}=-10 [/tex]
Squaring on both the sides of the equation, we get
[tex] 25(x+7)=100 [/tex]
[tex] x+7=4 [/tex]
x = -3
An extraneous solution is a root of a transformed equation but it is not a root of the original equation.
Here x= -3 is also a root of the transformed equation but it is not a root of the original equation as we can see in the given equation
[tex] 5\sqrt{x+7}=-10 [/tex]
As we put x = -3 in left hand side of the equation , we get
[tex] 5\sqrt{-3+7}= 5 \times \sqrt{4} = 10 [/tex] which is not equal to -10 that is the right hand side of the equation.
Therefore, x = -3 is an extraneous solution to the given equation.
So, Option B is the correct answer.
Answer:
I took the test its x=-3; extraneous
Step-by-step explanation:
