Respuesta :

The cubic function is [tex] f(x)=x^3-x^2-10x-8 [/tex]

Find the point at x=0,

Replace the variable x with 0 in f(x),

[tex] f(0)=0^3-0^2-10(0)-8=-8 [/tex]

Find the point at x=1,

Replace the variable x with 1 in f(x),

[tex] f(1)=1^3-1^2-10(1)-8=1-1-10-8=-18 \\ y=-18 [/tex]

Find the point at x=-1,

Replace the variable x with -1 in f(x):

[tex] f(-1)=(-1)^3-(-1)^2-10(-1)-8\\ =-1-1+10-8=0\\ y=0 [/tex]

Find the point at x=3,

REplace the variable x with 3 in f(x):

[tex] f(3)=3^3-3^2-10*3-8=-20 [/tex]

Similarly find few more points of this function:

f(-2)=0

f(2)=-24

f(5)=42

Now the cubic function [tex] f(x)=x^3-x^2-10x-8 [/tex] using the following points

x: -5 -1 0 1 2 3 5

y: - 108 0 -8 -18 -24 -20 42

Using this points now graph the function,

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