centripetal acceleration of the car=a= 1.46 m/s²
Explanation:
The velocity of an object moving around a circular path is given by
[tex] V=\frac{2\pi r}{T} [/tex]
T= time=280 s
r= radius of circular track=2.9 km= 2900 m
[tex] V= \frac{2\pi(2900)}{280} [/tex]
V=65 m/s
The centripetal acceleration is given by
[tex] a= \frac{v^2}{r} [/tex]
[tex] a= \frac{(65)^2}{2900} [/tex]
a= 1.46 m/s²
