Assuming the diameters of the nucleus and atom are 10−4 å and 1 - 5 å correspondingly, what fraction of the volume of the atom is taken up by the nucleus?

Respuesta :

The diameter of nucleus = 10₁[tex]10^{-4}[/tex] A° and atom = 1.5 A°. Radius of nucleus = [tex]\frac{10^{-4} }{2}[/tex] A° and radius of atom = [tex]\frac{1.5}{2}[/tex] A°. The fraction of volume taken by nucleus = [tex]\frac{volume of nuclues}{Volume of atom}[/tex] = [tex]\frac{4}{3}\pi\(\frac{(10^{-4} }{2})^{3}[/tex]/[tex]\frac{4}{3}\pi\(\frac{(10^{-4} }{2})^{3}[/tex].

Or, [tex]\frac{10^{-4} }{1.5})^{3}[/tex]= 2.95×[tex]10^{-13}[/tex]. This is the fraction of volume of nucleus in atom.