In this question, it is given that
A certain bacteria culture grows at a rate of 18% everyday. There are currently 420 bacteria.
And we have to find number of bacterias on day *.
For that we use the following formula
[tex]N(t) =N_{0} (1 +r)^t[/tex]
[tex]N(0)= 420, r = 0.18 , and \ t = 8days[/tex]
Substituting these values in the formula, we will get
[tex]N(8)= 420(1+0.18)^8
\\
N(8)=1579[/tex]
THerefore on day 8, number of bacterias are 1579.
