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When added to a sealed flask and heated, 6.0g of carbon and 16.0 g of oxygen react to form22.0 g of carbon dioxide. how much carbondioxide is formed when 12.0 g of carbon isreacted with 100.0 g of oxygen?

Respuesta :

6 g C/22 g CO2 = 24 g C/X
X=88.0 g
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Answer:

44.0g of CO2 is formed.

Explanation:

Using law of definite proportion,

(6.0g/22)CO2 =0.2727g of Carbon

(12/22)CO2= 0.5455g of Oxygen

(12g of carbon)/( xg of CO2)= 0.2727

Xg of CO2= 12g/0.2727 =44.0g

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