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At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in the next 16.0 s? m (b) what is her final velocity? m/s

Respuesta :

given that initial velocity is

[tex]v_i = 11 m/s[/tex]

deceleration is given as

[tex]a = -0.3 m/s^2[/tex]

now we have to find the distance covered in 16 s

[tex]d = v_i * t + \frac{1}{2} at^2[/tex]

[tex]d = 11*16 - \frac{1}{2}*0.3*16^2[/tex]

[tex]d = 137.6 m[/tex]

so it will cover 137.6 m distance

part b)

in order to find the final speed

[tex]v_f = v_i + at[/tex]

[tex]v_f = 11 - 0.3*16[/tex]

[tex]v_f = 6.2 m/s[/tex]

so its speed will be 6.2 m/s

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