we are given a 50% (m/v) solution of sucrose and initial volume = 33 ml
It implies mass of sucrose in this solution = (50×33 ) / 100 = 16.5 grams
∴ moles of sucrose in solution = mass of sucrose / molar mass of sucrose
= 16.5 g÷ (342.3 g/mol) = 0.0482 moles
Now after accidentally adding water only the volume of solution changes but the moles of sucrose remains same.
Thus, new volume = 33 ml + 50 ml = 83 ml = 0.083 L
we know, molarity is defined as number of moles of solute per volume of solution in L.
∴ Molarity of new solution = 0.0482 moles ÷ 0.083 L
= 0.5807 M
Ans- 0.5807 M
