Respuesta :
This is written in vertex form:-
y = a(x - b)^2 + c where (b, c) is the vertex.
Comparing the function in the question to the above:-
b = -2 and c = 0 so the vertex is at the point (-2, 0) answer
The y intercept occurs when x = 0 so here it is:-
-1.5( 0 + 2)^2 = -6
y intercept is at ( 0, -6) answer
Answer:
The vertex = (-2, 0)
The y-intercept of the equation is -6.
Step-by-step explanation:
Since, the vertex form of quadratic equation,
[tex]y=a(x-h)^2+k[/tex]
Where, (h,k) is the vertex of the equation,
Here, the given equation,
[tex]y = -1.5(x + 2)^2[/tex]
[tex]\implies y=-1.5(x-(-2))^2+0[/tex]
By comparing,
The vertex = (-2, 0)
Now, for y-intercept,
x = 0,
[tex]y=-1.5(0+2)^2=-1.5(4)=-6[/tex]
Hence, y-intercept of the equation is -6.
