Seagull is at height 11 m
it drops a shell from rest
so here we know that
acceleration of shell is due to free fall = -9.81 m/s^2
displacement = - 11 m
initial speed = 0
now we will use kinematics equation here in order to find the final speed
[tex]v_f^2 = vi^2 + 2as[/tex]
now plug in all values in it
[tex]v_f^2 = 0 + 2*(-9.81)*(-11)[/tex]
[tex]v_f^2 = 215.82[/tex]
[tex]v_f = 14.7 m/s[/tex]
so here the speed by which shell will strike with the rocks is 14.7 m/s
