Answer
0.238 Kg
Explanation
specific latent heat of fusion = 0.336 MJ/kg.
Specific heat capacity of water = 4200 J/kgK
Specific heat capacity of ice = 2100 J/kgK
Heat = mLf + mcΔθ + mcΔθ
(change of state) + (heat gained by ice) + (heat gained by water)
9.8 ✕ 10⁵ J = ( 336,000m) + (2100×12m) + (4200×12m)
98000 = m(336000 + 25200 + 50,400)
98000 = 411,600m
m = 98000/411600
= 0.238 Kg
