Given:
E = 7.3 × 10–17 Hz
h= 6.63 × 10–34 J•s
Now E = hf
where E is the energy of the photon
h is the Planck's constant
f is the frequency of the photon
Substituting the values in the equation we get
E= 7.3 × 10^-17 × 6.63 × 10^-34
E= 4.8399 × 10^-50 J.
The energy of the photon, to the nearest tenths place, is 4.8399 × 10⁻⁵⁰ J.
Energy of the photon can be calculated as :
E = hυ, where
E = energy of the photon = to find?
h = plank's constant = 6.63 × 10⁻³⁴ J•s (given)
and υ = frequency = 7.3 × 10⁻¹⁷ Hz
Now putting all these values in the above equation, we get
E = (6.63 × 10⁻³⁴) × (7.3 × 10⁻¹⁷)
E = 4.8399 × 10⁻⁵⁰ J.
Hence, 4.8399 × 10⁻⁵⁰ J is the energy of the photon.
To learn more about energy of photon, visit the below link:
https://brainly.com/question/15946945
