Answer:
vertical distance, s = 0.16 meters
Explanation:
It is given that,
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.
Dashboard is placed at a distance of 2.7 meters.
Calculating time from velocity and distance i.e. [tex]t=\dfrac{d}{s}=\dfrac{2.7}{15}\ s=0.18\ s[/tex]
Using second equation of motion for finding vertical distance :
[tex]s=ut+0.5gt^2[/tex]
Here, u = 0 (for vertical velocity )
[tex]s=0.5gt^2[/tex]
[tex]s=0.5\times 10\times (0.18)^2[/tex]
s = 0.162 meters
or s = 0.16 meters
Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.
