Given:
u= 0.91 m/s
a=0.31m/s∧2
s= 0.61 m
s = ut +1/2(at∧2)
where s is the displacement of the object
u is the initial velocity
t is the time
a is the acceleration
Substituting the values
0.61=0.91×t +(0.31 ×t∧2)/2
0.61=0.91 t + 0.155 t∧2
t=0.61 secs
Consider the equation
v=u +at
where v is the initial velocity
u is the initial velocity
a is the acceleration
t is the time
Substituting the values we get
v= 0.91 +(0.31×0.61)
v= 1.099 m/s
