#2
As it is given here
initial speed is
[tex]v_i = 6 m/s[/tex]
After 4 seconds the final speed is
[tex]v_f = 14 m/s[/tex]
so here we can use the formula of acceleration using kinematics
[tex]a = \frac{v_f - v_i}{t}[/tex]
[tex]a = \frac{14 - 6}{4}[/tex]
[tex]a = 2 m/s^2[/tex]
so here it will accelerate at 2 m/s^2 rate.
#3
As it is given here
initial it starts from rest
[tex]v_i = 0 m/s[/tex]
After 2.5 seconds the final speed is
[tex]v_f = 15 m/s[/tex]
so here we can use the formula of acceleration using kinematics
[tex]a = \frac{v_f - v_i}{t}[/tex]
[tex]a = \frac{15 - 0}{2.5}[/tex]
[tex]a = 6 m/s^2[/tex]
so here it will accelerate at 6 m/s^2 rate.
#4
i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.
