Answer : 2.0 mph
Haji rows his canoe 10 mph in still water
Speed of still water = 10 mph
Let the speed of the current = x
Upstream speed = 10 - x
Downstream speed = 10+x
Upstream Distance = 4 miles
Downstream Distance = 6 miles
[tex]Time = \frac{Distance}{speed}[/tex]
Time taken on upstream = [tex]\frac{4}{10-x}[/tex]
Time taken on downstream = [tex]\frac{6}{10+x}[/tex]
Same time taken for both upstream and downstream
So [tex]\frac{4}{10-x} = \frac{6}{10+x}[/tex]
Cross multiply it
4(10+x) = 6(10-x)
40 + 4x = 60 -6x
Add 6x and subtract 40 on both sides
10x = 20 (divide by 10)
x= 2
So speed of the current = 2.0 mph
The approximate speed of the current that day is 2.0 mph.\
The correct option is A.
Given
The speeds of the current = x
Upstream speed = 10 - x
Downstream speed = 10+x
Upstream Distance = 4 miles
Downstream Distance = 6 miles
Speed is defined as the fraction of the total distance and time taken to complete it.
The following formula is used to calculate speed;
[tex]\rm Speed =\dfrac{Distance}{Time}[/tex]
Therefore,
The approximate speed of the current that day is;
[tex]\rm = \dfrac{Upstream \ distaance}{Upstream \ speed}= \dfrac{downstream \ distaance}{downstream \ speed}\\\\ \dfrac{4}{10-x}=\dfrac{6}{10+x}\\\\4(10+x)=6(10-x)\\\\40+4x=60-6x\\\\4x+6x=60-40\\\\10x=20\\\\x= \dfrac{20}{10}\\\\x=2[/tex]
Hence, the approximate speed of the current that day is 2.0 mph.
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