Answer:
Option C
Step-by-step explanation:
given two equations
6m-5n= 14 ... i
2m+2n= -10 ...ii
We can solve this by elimination.
For elimination consider the coefficients of m.
They are 6 and 2, with LCD 6
You multiply 2nd equation by 3 to have
6m+6n =-30 ... iii and
6m-5n = 14 ... i
Subtract i from iii
11n = -44
Divide by 11 to get n
n = -4
Substitute in I equation
6m-5(-4) =14
6m +20 = 14
subtract 20
6m =14-20 =-6
divide by 6
m =-1
Hence answer is m=-1 and n=-4
(-1,-4)
Option C is the answer.
